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Old 22-02-2008, 07:26 PM   #21
cosmin targoviste
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Si raspunsul la prima problema era mai inteligent?Mai cati oameni inteligenti pe aici.Stiti ce?M-am saturat de fitele unora, mai lasati-ma in pace!
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Old 22-02-2008, 07:39 PM   #22
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Am rezolvat problema asta acum vreo 2 ani .Stiam ca el e...IN mamica,dar vroiam sa fiu mai politicos,mai sunt si copii p-aci.
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Old 22-02-2008, 07:40 PM   #23
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La prima problema s-a ajuns la un raspuns prin calcule.
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Old 22-02-2008, 07:53 PM   #24
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O nou problema...ceva mai usoara (ca sa va faceti incalzirea pentru urmatoarea)

1 2 3 4 5 6 7 8 9 = 100

Numerele de mai sus fac parte dintr-o ecuatie in care "+"-urile si "-"-urile din partea stanga a acesteia au fost scoase. In plus, doua dintre acele cifre formeaza defapt un numar de doua cifre


Puneti "+"-urile si "-"-urile astfel incat ecuatia sa functioneze.
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Last edited by DarkComy; 22-02-2008 at 08:09 PM.
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Old 22-02-2008, 08:26 PM   #25
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1+2+3-4+5+6+78+9=100
-1+2-3+4+5+6+78+9=100
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Old 22-02-2008, 08:42 PM   #26
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5+5+5=550

Puteti sa folositi doar o singura linie(- | \ /) pentru ca propozitia sa fie adevarata
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Old 22-02-2008, 08:49 PM   #27
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Quote:
Originally Posted by http View Post
5+5+5=550

Puteti sa folositi doar o singura linie(- | \ /) pentru ca propozitia sa fie adevarata
Pui un "/" peste egal?
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Old 22-02-2008, 09:22 PM   #28
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nu,va zic raspunsul?
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Old 22-02-2008, 10:47 PM   #29
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Pui un "/" peste primul sau al doilea plus si iese un 4. => 545+5=550 sau 5+545=550.
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Old 22-02-2008, 11:53 PM   #30
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Cate pozitii posibile exista pentru aranjarea a 4 baieti si 4 fete alternativ(adica un baiat , o fata , un baiat , o fata etc.) in jurul unei mese rotunde.
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